6y^2+10y-16=0

Solution for 6y^2+10y-16=0 equation:

6y^2+10y-16=0

a = 6; b = 10; c = -16;
Δ = b2-4ac
Δ = 102-4·6·(-16)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-22}{2*6}=\frac{-32}{12}
=-2+2/3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+22}{2*6}=\frac{12}{12}
=1
$